c^2+8c-48=0

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Solution for c^2+8c-48=0 equation:


Simplifying
c2 + 8c + -48 = 0

Reorder the terms:
-48 + 8c + c2 = 0

Solving
-48 + 8c + c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(-12 + -1c)(4 + -1c) = 0

Subproblem 1

Set the factor '(-12 + -1c)' equal to zero and attempt to solve: Simplifying -12 + -1c = 0 Solving -12 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '12' to each side of the equation. -12 + 12 + -1c = 0 + 12 Combine like terms: -12 + 12 = 0 0 + -1c = 0 + 12 -1c = 0 + 12 Combine like terms: 0 + 12 = 12 -1c = 12 Divide each side by '-1'. c = -12 Simplifying c = -12

Subproblem 2

Set the factor '(4 + -1c)' equal to zero and attempt to solve: Simplifying 4 + -1c = 0 Solving 4 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + -1c = 0 + -4 Combine like terms: 4 + -4 = 0 0 + -1c = 0 + -4 -1c = 0 + -4 Combine like terms: 0 + -4 = -4 -1c = -4 Divide each side by '-1'. c = 4 Simplifying c = 4

Solution

c = {-12, 4}

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